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13430=243x-x^2
We move all terms to the left:
13430-(243x-x^2)=0
We get rid of parentheses
x^2-243x+13430=0
a = 1; b = -243; c = +13430;
Δ = b2-4ac
Δ = -2432-4·1·13430
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-243)-73}{2*1}=\frac{170}{2} =85 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-243)+73}{2*1}=\frac{316}{2} =158 $
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